SOLUTION: "A rectangle’s 102 in perimeter is . Its length is 5 in longer than its width. Use an equation to find the rectangle’s length and width." How do I set up the equation?

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: "A rectangle’s 102 in perimeter is . Its length is 5 in longer than its width. Use an equation to find the rectangle’s length and width." How do I set up the equation?       Log On


   

Question 1187111: "A rectangle’s 102 in perimeter is . Its length is 5 in longer than its width. Use an equation to find the rectangle’s length and width." How do I set up the equation?
Found 2 solutions by Alan3354, MathTherapy:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
"A rectangle’s 102 in perimeter is . [sic] Its length is 5 in longer than its width. Use an equation to find the rectangle’s length and width." How do I set up the equation?
-----------------------
P = 2W + 2L = 102 you don't know that?
-----
L = 2W + 5
-----
That's how.

Answer by MathTherapy(10555) About Me  (Show Source):
You can put this solution on YOUR website!

"A rectangle’s 102 in perimeter is . Its length is 5 in longer than its width. Use an equation to find the rectangle’s length and width." How do I set up the equation?
Correct equations:  

Reduce the 1st equation to get a simpler one.

Substitute the 2nd into the reduced version of the 1st and solve for W. Then find L, the length.