Question 1177453: In order to raise money for team towels, your swim team decides to sell pizza and subs. The profits are $2.75 and $1.45 for for each sub. You sell 48 subs. Write and solve an inequality to determine the number of pizzas you must sell to have a total profit of at least $100.
Your calling card charges $1.25 to place a call plus $0.35 for each minute. Write and solve an inequality to determine how long a call can last so that the total cost stays below $5.
Answer by CPhill(1959)   (Show Source):
You can put this solution on YOUR website! **Pizza and Subs**
Let's break down the pizza and subs problem:
**1. Define a variable:**
* Let 'p' be the number of pizzas you need to sell.
**2. Write the inequality:**
* Profit from pizzas: $2.75p
* Profit from subs: $1.45 * 48 = $69.60
* Total profit: $2.75p + $69.60
* We want the total profit to be at least $100, so the inequality is:
$2.75p + $69.60 ≥ $100
**3. Solve the inequality:**
* Subtract $69.60 from both sides: $2.75p ≥ $30.40
* Divide both sides by $2.75: p ≥ 11.05
Since you can't sell parts of pizzas, you need to sell at least 12 pizzas.
**Answer:** You must sell at least 12 pizzas to have a total profit of at least $100.
**Calling Card**
Now let's solve the calling card problem:
**1. Define a variable:**
* Let 'm' be the number of minutes the call can last.
**2. Write the inequality:**
* Cost of the call: $1.25 + $0.35m
* We want the total cost to stay below $5, so the inequality is:
$1.25 + $0.35m < $5
**3. Solve the inequality:**
* Subtract $1.25 from both sides: $0.35m < $3.75
* Divide both sides by $0.35: m < 10.71
**Answer:** The call can last for a maximum of 10 minutes to keep the total cost below $5.
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