SOLUTION: Using the system you selected above, solve the system of equations.
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Jesse and Adam are both selling items to raise money for Baseball uniforms. They are e
Question 1171212: Using the system you selected above, solve the system of equations.
Show/ upload all work.
Jesse and Adam are both selling items to raise money for Baseball uniforms. They are each selling
two items: chocolate bars and candles. Jesse sells 12 chocolate bars and 7 candles and makes a
total of $94. Adam sells 24 chocolate bars and 5 candles and makes a total of $98. How much does
one chocolate bar and one candle cost?
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Jesse and Adam are both selling items to raise money for Baseball uniforms. They are each selling
two items: chocolate bars and candles. Jesse sells 12 chocolate bars and 7 candles and makes a
total of $94. Adam sells 24 chocolate bars and 5 candles and makes a total of $98. How much does
one chocolate bar and one candle cost?
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12H + 7C = 94 (1) (H stands for chocolate bars; C stands for candles)
24H + 5C = 98 (2)
Multiply equation (1) by 2 (both sides). Keep equation (2) as is. You will get
24H + 14C = 188 (1')
24H + 5C = 98 (2')
Now subtract equation (2') from equation (1').
The terms "24H" will cancel each other, and you will get a single equation in one unknown C
14C - 5C = 188 - 98
9C = 90
C = 90/9 = 10.
Thus the cost of each candle is $10.
To find another unknown, H, substitute the found valu C into equation (1). You will get
12*H + 7*10 = 94
12H = 94 - 70 = 24
H = 24/12 = 2.
ANSWER. $2 per chocolate bar and $10 for each candle.
Solved.
From my solution, learn on how the ELIMINATION method works.
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I remember that in my previous post I showed you, how to solve this problem MENTALLY.
