SOLUTION: The value of a stock, A(x), over a year long period decreased and then increased according to the quadratic function A(x)=0.75x^2-6x+20, where x represents the number of months pa

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: The value of a stock, A(x), over a year long period decreased and then increased according to the quadratic function A(x)=0.75x^2-6x+20, where x represents the number of months pa      Log On


   

Question 1162574: The value of a stock, A(x), over a year long period decreased and then increased according to the quadratic function A(x)=0.75x^2-6x+20, where x represents the number of months passed since you invested. The value of another stock, B(x), increased linearly according to the equation B(x)=2.75x+1.50 over the same year. After how long are both stocks worth the same amount?
Answer by ikleyn(52915) About Me  (Show Source):
You can put this solution on YOUR website!
.

To find these months when A(x) = B(x), you need to solve this quadratic equation


    0.75x^2 - 6x + 20 = 2.75x + 1.50.


Reduce it to the standard form quadratic equation. 
Then solve using the quadratic formula.