Question 1160801: A toy rocket launched into the air has a height (h feet) at any given time (t seconds) as
h = -16t2 + 160t until it hits the ground. At what time(s) is it at a height of 9 feet above the ground?
Answer by ikleyn(52835) (Show Source):
You can put this solution on YOUR website! .
To answer the question, you need to solve the equation
h(t) = 9,
which is
-16t^2 + 160t = 9.
You write it in the standard form
16t^2 - 160t + 9 = 0
and solve using the quadratic formula.
Happy solving (!)
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