SOLUTION: On a bicycle, Kristen rides for 2 hours and is 18 miles from her house. After riding for 12 hours, she is 98 miles away. Write an equation to model this situation (use m for mil

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Question 1160320: On a bicycle, Kristen rides for 2 hours and is 18 miles from her house. After riding for 12 hours, she is 98 miles away.
Write an equation to model this situation (use m for miles and h for hours).
Found 3 solutions by Alan3354, ikleyn, greenestamps:
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website!
On a bicycle, Kristen rides for 2 hours and is 18 miles from her house. After riding for 12 hours, she is 98 miles away.
Write an equation to model this situation (use m for miles and h for hours).
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Assuming constant speed:
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Find the speed.
(98-18) miles/(12-2)hours = 8 mi/hr (between the 2 points)
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For distance as a function of time:
m = 8*h + 18
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The 1st 2 hours she goes 18/2 = 9 mi/hr
That creates a non-linear function for the 12 hours.
More info needed to know what to do about that.

Answer by ikleyn(52782)   (Show Source):
You can put this solution on YOUR website!
.

Check your post.

As it is worded, printed and presented, I do not see any sense in it.

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Other tutors find different ways to interpret your post;

which means that the post is NOT a Math problem, at all.

Its meaning is the subject of guessing . . .

Answer by greenestamps(13200)   (Show Source):
You can put this solution on YOUR website!

In the additional 12-2 = 10 hours, the additional distance she rides is 98-18 = 80 miles. So her speed is 80/10 = 8mph.

The linear equation for the distance from her house is y = ax+b -- or, using m for miles and h for hours, m = ah+b.

In that equation, a is the slope (her speed) and b is the y-intercept, which in this problem is her distance from her house when she starts riding.

We have determined that her speed a is 8; to determine b we use either given data point.

At 2 hours, she was 18 miles from her house:

She started her ride 2 miles from her house.

The linear equation for her distance from her house is