SOLUTION: The perimeter of a rectangle is 8 inches. The length of the rectangle is one inch more than twice the width of the rectangle. Find the dimensions of the rectangle.

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Question 1151116: The perimeter of a rectangle is 8 inches. The length of the rectangle is one inch more than twice the width of the rectangle. Find the dimensions of the rectangle.
Found 3 solutions by Alan3354, math_helper, MathLover1:
Answer by Alan3354(69443) About Me  (Show Source):
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The perimeter of a rectangle is 8 inches. The length of the rectangle is one inch more than twice the width of the rectangle. Find the dimensions of the rectangle.
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L + W = 4
L = 2W + 1
Can you do the rest?

Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!
2L + 2W = 8
L = 1 + 2W

Putting these together:

2(1+2W) + 2W = 8
2 + 4W + 2W = 8
6W = 6 --> +green%28+W+=+1+%29+ ==> +green+%28+L+=+3+%29

Check: 2L+2W = 2(3)+2(1) = 6+2 = 8

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

The perimeter of a rectangle is 8+inches.
2%28a%2Bb%29=8
a%2Bb=4
a=4-b.......eq.1
if the length a of the rectangle is 1 inch more+than twice the width of the rectangle b, we have
a=2b%2B1 ......eq.2
from eq.1 and eq.2 we have
4-b=2b%2B1
4-1=2b%2Bb
3=3b
b=1
find a
a=4-1.......eq.1
a=3
the length of the rectangle is 3 inches
the width of the rectangle is 1 inch