Question 1143855: A school district purchases a high volume printer, copier, and scanner for $25,000. After 10 years, equipment all had to be replaced. It’s value at that time is expected to be $2000. Write a linear equation giving the value of the equipment for each year tea during its 10 years of use.
Found 2 solutions by ankor@dixie-net.com, Theo:
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! A school district purchases a high volume printer, copier, and scanner for $25,000.
After 10 years, equipment all had to be replaced.
It’s value at that time is expected to be $2000.
Write a linear equation giving the value of the equipment for each year tea during its 10 years of use.
:
Let y the value of the printer after x years
x1 = 0, y1 = 25000
x2 = 10, y2 = 2000
Slope (m): =  = 23000/-10 = -2300
:
the point/slope form y - y1 = m(x - x1)
y - 25000 = -2300(x-0)
y = -2300x + 25000
Answer by Theo(13342)  (Show Source):
You can put this solution on YOUR website! the value went from 25000 to 2000 in 10 years.
the loss in value each year is (25000 - 2000) / 10 = 23000 / 10 = 2300.
linear equation form is y = mx + x
m is the slope.
b is the y-intercept.
y is the value.
x is the number of years.
the slope becomes -2300 because it's a loss each year.
you have two coordinate points on the line.
they are (0,25,000) and (10,2000)
since the slope is -2300, the general form of the equation becomes y = -2300 * x + b
to find the value of b, replace (x,y) with the value for one of the points and then solve for b.
i used the point (0,25000)
the equation of y = -2300 * x + b becomes 25000 = -2300 * 0 + b
simplify to get 25000 = b.
you have m = -2300 and b = 25000, so the equation becomes y = -2300 * x + 25000
solve this equation for x = 0 and for x = 10.
when x = 0, y = 25000
when x = 10, y = -2300 * 10 + 25000 = -23000 + 25000 = 2000.
the equation is good.
the equation can be graphed as shown below:
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