SOLUTION: A metallurgist has one alloy containing 22% copper and another containing 53% copper. How many pounds of each alloy must she use to make 51 pounds of a third alloy containing 30% c

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Question 1103547: A metallurgist has one alloy containing 22% copper and another containing 53% copper. How many pounds of each alloy must she use to make 51 pounds of a third alloy containing 30% copper?
Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.
Copper + copper      = copper

0.22*x + 0.53*(51-x) = 0.3*51  ====>

0.22x + 0.53*51 - 0.53x = 0.3*51,

-0.31x = 0.3*51 - 0.53*51 = -0.23*51  ====>  x = %28-0.23%2A51%29%2F%28-0.31%29 = %2823%2A51%29%2F31 = 37.839.


Answer.  37.839 pounds of the 22% alloy and (51-37.839) = 13.161 of the 53% alloy must be used.


Check.   0.22*37.839 + 0.53*13.161 = 15.3  pounds of copper;

         51*0.3 = 15.3 pounds of copper.    ! Correct !

Solved.

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There is entire bunch of introductory lessons covering various types of mixture problems
    - Mixture problems
    - More Mixture problems
    - Solving typical word problems on mixtures for solutions
    - Word problems on mixtures for antifreeze solutions
    - Word problems on mixtures for alloys
    - Typical word problems on mixtures from the archive
in this site.

You will find there ALL TYPICAL mixture problems with different methods of solutions,
explained at the different levels of detalization, from very detailed to very short.

Read them and become an expert in solution mixture word problems.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this textbook in the section "Word problems" under the topic "Mixture problems".


Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.