SOLUTION: On Saturday morning, lynn walked for 2 hours and then ran for 45 minutes. If she ran twice as fast as she walked and she covered 14 miles altogether, then how fast did she walk?

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: On Saturday morning, lynn walked for 2 hours and then ran for 45 minutes. If she ran twice as fast as she walked and she covered 14 miles altogether, then how fast did she walk?      Log On


   



Question 1071492: On Saturday morning, lynn walked for 2 hours and then ran for 45 minutes. If she ran twice as fast as she walked and she covered 14 miles altogether, then how fast did she walk?
Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!
Let w be the speed at which Lynn walked.
Then 2w is the speed at which Lynn ran.
(2hrs)(w mi/hr) + (45/60 hr)(2w mi/hr) = 14 mi
I'll drop the units while solving for w:
2w + (45/60)(2w) = 14
2w + 1.5w = 14
3.5w = 14
w = 14/3.5
w = 4 mi/hr (her speed while walking)
This implies 2w = 8 mi/hr (her speed while running)

Ans: Lynn walked at +highlight%284%29+mi/hr

Check: 4mi/hr * 2hr + 8mi/hr*0.75hr = 8mi + 6mi = 14mi (ok)