SOLUTION: A truck radiator holds 135 liters of fluid. How much pure antifreeze must be added to a mixture that is 10​% antifreeze in order to fill the radiator with a mixture that is 2
Question 1062016: A truck radiator holds 135 liters of fluid. How much pure antifreeze must be added to a mixture that is 10% antifreeze in order to fill the radiator with a mixture that is 20% antifreeze? Answer by ikleyn(52781) (Show Source):
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A truck radiator holds 135 liters of fluid. How much pure antifreeze must be added to a mixture that is 10% antifreeze in order to
fill the radiator with a mixture that is 20% & antifreeze?
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Let A be the required amount of the pure antifreeze, in liters.
Then the volume of the 10% antifreeze mixture to mix with the pure antifreeze is (135-A) liters.
The antifreeze balance equation is
= 0.2*135.
Solve for A.