SOLUTION: A farmer bought 3 cows and 6 horses for $8,700. A couple of months later he bought 6 cows and 2 horses for $7,900. If the price of each horse and each cow did not change

Algebra ->  Coordinate Systems and Linear Equations  -> Lessons  -> Linear Equations Lesson -> SOLUTION: A farmer bought 3 cows and 6 horses for $8,700. A couple of months later he bought 6 cows and 2 horses for $7,900. If the price of each horse and each cow did not change      Log On


   

Question 878310: A farmer bought 3 cows and 6 horses for $8,700. A couple of months
later he bought 6 cows and 2 horses for $7,900. If the price of
each horse and each cow did not change, what is the price of each
cow?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi

3c + 6h = 8700  |times -2 and ADD EQs

6c + 2h = 7900

       -10h = -9500

          h = $950  and c = $1000  3c+=+8700+-+6%2A950+=+3000