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3x-2 = 15x-2y = 5
Make two equations:
3x-2 = 15x-2y
(1) 15x-2y = 5
Simplify the first equation:
3x-2 = 15x-2y
(2) -12x+2y = 2
Put equations (1) and (2) together as a system to solve
by elimination:
(1) 15x-2y = 5
(2) -12x+2y = 2
Add the two equations term by term
(1) 15x-2y = 5
(2) -12x+2y = 2
-----------------
3x = 7
x = 7/3
Substitute 7/3 for x in (1)
(1) 15x-2y = 5
15(7/3)-2y = 5
35-2y = 5
-2y = -30
y = 15
Solution x = 7/3, y = 15.
Edwin