SOLUTION: this is solving two equations using substitution. 4x+3y=15 and 5x-2y=13. I have tried: 4x+3y=15 subtracted 4 from both sides and then divided it by 3 to get the y by its self and

Algebra ->  Coordinate Systems and Linear Equations  -> Lessons  -> Linear Equations Lesson -> SOLUTION: this is solving two equations using substitution. 4x+3y=15 and 5x-2y=13. I have tried: 4x+3y=15 subtracted 4 from both sides and then divided it by 3 to get the y by its self and      Log On


   

Question 742294: this is solving two equations using substitution.
4x+3y=15 and 5x-2y=13. I have tried: 4x+3y=15 subtracted 4 from both sides and then divided it by 3 to get the y by its self and then I plugged it into the second equation but I cant find the correct answer after this.
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
4x+3y=15 and 5x-2y=13.

" tried: 4x+3y=15 subtracted 4 from both sides and then divided it by 3 to get the y by its self and then I plugged it into the second equation but "

First Equation: 4x%2B3y=15
3y=15-4x
y=15%2F3-4x%2F3=5-%284%2F3%29x

Second Equation: 5x-2%28y%29=13
5x-2%285-4x%2F3%29=13, the substitution
5x-10%2B8x%2F3=13
5x%2B8x%2F3-10=13
%285%2B8%2F3%29x=13%2B10
%2815%2F3%2B8%2F3%29x=23
%2823%2F3%29x=23
x=23%2A%283%2F23%29
Final Answer for x: highlight%28x=3%29