SOLUTION: Please help me solve this problem. I need to solve by using the elimination method. 6x+7y=6 x=48-9y

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Question 403540: Please help me solve this problem.
I need to solve by using the elimination method.
6x+7y=6
x=48-9y

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

6x%2B7y=6
x=48-9y or x+%2B+9y+=48

Solved by pluggable solver: Solving a System of Linear Equations by Elimination/Addition


Lets start with the given system of linear equations

6%2Ax%2B7%2Ay=6
1%2Ax%2B9%2Ay=48

In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa).

So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero.

So to make the x coefficients equal but opposite, we need to multiply both x coefficients by some number to get them to an equal number. So if we wanted to get 6 and 1 to some equal number, we could try to get them to the LCM.

Since the LCM of 6 and 1 is 6, we need to multiply both sides of the top equation by 1 and multiply both sides of the bottom equation by -6 like this:

1%2A%286%2Ax%2B7%2Ay%29=%286%29%2A1 Multiply the top equation (both sides) by 1
-6%2A%281%2Ax%2B9%2Ay%29=%2848%29%2A-6 Multiply the bottom equation (both sides) by -6


So after multiplying we get this:
6%2Ax%2B7%2Ay=6
-6%2Ax-54%2Ay=-288

Notice how 6 and -6 add to zero (ie 6%2B-6=0)


Now add the equations together. In order to add 2 equations, group like terms and combine them
%286%2Ax-6%2Ax%29%2B%287%2Ay-54%2Ay%29=6-288

%286-6%29%2Ax%2B%287-54%29y=6-288

cross%286%2B-6%29%2Ax%2B%287-54%29%2Ay=6-288 Notice the x coefficients add to zero and cancel out. This means we've eliminated x altogether.



So after adding and canceling out the x terms we're left with:

-47%2Ay=-282

y=-282%2F-47 Divide both sides by -47 to solve for y



y=6 Reduce


Now plug this answer into the top equation 6%2Ax%2B7%2Ay=6 to solve for x

6%2Ax%2B7%286%29=6 Plug in y=6


6%2Ax%2B42=6 Multiply



6%2Ax=6-42 Subtract 42 from both sides

6%2Ax=-36 Combine the terms on the right side

cross%28%281%2F6%29%286%29%29%2Ax=%28-36%29%281%2F6%29 Multiply both sides by 1%2F6. This will cancel out 6 on the left side.


x=-6 Multiply the terms on the right side


So our answer is

x=-6, y=6

which also looks like

(-6, 6)

Notice if we graph the equations (if you need help with graphing, check out this solver)

6%2Ax%2B7%2Ay=6
1%2Ax%2B9%2Ay=48

we get



graph of 6%2Ax%2B7%2Ay=6 (red) 1%2Ax%2B9%2Ay=48 (green) (hint: you may have to solve for y to graph these) and the intersection of the lines (blue circle).


and we can see that the two equations intersect at (-6,6). This verifies our answer.