SOLUTION: A store owner has two different blends of coffee. Brand A sells for $10.50/lb and Brand B sells for $5.75/lb. The owner wants to create a 25 lb mixture of Brand A and B to sell for

Algebra ->  Coordinate Systems and Linear Equations  -> Lessons  -> Linear Equations Lesson -> SOLUTION: A store owner has two different blends of coffee. Brand A sells for $10.50/lb and Brand B sells for $5.75/lb. The owner wants to create a 25 lb mixture of Brand A and B to sell for      Log On


   



Question 271155: A store owner has two different blends of coffee. Brand A sells for $10.50/lb and Brand B sells for $5.75/lb. The owner wants to create a 25 lb mixture of Brand A and B to sell for $8.22 a pound. How much of each blend should he use?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
In words:
(cost of Brand A in mix) + (cost of brand B in mix) = cost of mix
which is the same as:
(pounds of Brand A in mix) x (cost per pound) + (pounds of brand B in mix) x (cost per pound) = pounds of mix) x (cost per pound of mix)
Let A = pounds of brand A in mix
Let B = pounds of brand B in mix
(1) A+%2B+B+=+25
A%2A10.5+%2B+B%2A5.75+=+25%2A8.22
Multiply both sides by 100
(2) 1050A+%2B+575B+=+20550
and, from (1),
(1) B+=+25+-+A
By substitution:
(2) 1050A+%2B+575%2A%2825-+A%29+=+20550
1050A+%2B+14375+-+575A+=+20550
475A+=+6175
A+=+13
and, since
B+=+25+-+A
B+=+25+-+13
B+=+12
He needs 13 pounds of brand A and 12 pounds of brand B
check:
A%2A10.5+%2B+B%2A5.75+=+25%2A8.22
13%2A10.5+%2B+12%2A5.75+=+25%2A8.22
136.5+%2B+69+=+205.5
205.5+=+205.5
OK