SOLUTION: I don't under stand how come i have to put 3x to the right and divide by 2 on this question, (3x + 2y = 6) and i really just don't understand how to do these

Algebra ->  Coordinate Systems and Linear Equations  -> Lessons  -> Linear Equations Lesson -> SOLUTION: I don't under stand how come i have to put 3x to the right and divide by 2 on this question, (3x + 2y = 6) and i really just don't understand how to do these      Log On


   



Question 251638: I don't under stand how come i have to put 3x to the right and divide by 2 on this question, (3x + 2y = 6) and i really just don't understand how to do these
Found 2 solutions by stanbon, padmameesala:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
I don't under stand how come i have to put 3x to the right and divide by 2 on this question, (3x + 2y = 6) and i really just don't understand how to do these
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If you want to write the equation in slope-intercept
form you have to isolate "Y" on one side of the equal sign.
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Start: 3x + 2y = 6
Subtract 3x from both sides to get:
2y = -3x+6
Divide both sides by 2 to isolate "y":
y = (-3/2)x+3
==================
Cheers,
Stan H.

Answer by padmameesala(42) About Me  (Show Source):
You can put this solution on YOUR website!
3x + 2y =6
-3x -3x subtract 3x on both sides inorder to balance the equation
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2y = 6 -3x
-- -----
2 2 divide by 2 on both sides inorder to balance the equation
y = (6-3x)/2
this is the way it is solved
hope you will understand
wish you good luck!