SOLUTION: 3x+y=6 6x+2y=10 Use substitution method to solve this system

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Question 179543This question is from textbook Academic Systems Elementar Algebra Personal Academic Notebook
: 3x+y=6
6x+2y=10
Use substitution method to solve this system This question is from textbook Academic Systems Elementar Algebra Personal Academic Notebook

Answer by jojo14344(1513) About Me  (Show Source):
You can put this solution on YOUR website!

Givensystem%283x%2By=6%28EQN1%29%2C6x%2B2y=10+%28EQN2%29%29
In EQN 1, we get
y=6-3x%28EQN3%29, subst. in EQN 2
6x%2B2%286-3x%29=10
6x%2B12-6x=10---->cross%286x%29-cross%286x%29=10-12
0=-2 ---> This means these 2 Line Eqn's don't INTERSECT, but rather they're PARALLEL.
Via Slope-Intercept Form: y=mx%2Bb
In EQN 3, y=6-3x
Let f%28x%29=0
y=6-3%280%29
highlight%28y=6%29
Letf%28y%29=0
0=6-3x
3x=6--->cross%283%29x%2Fcross%283%29=cross%286%292%2Fcross%283%29
highlight%28x=2%29
In EQN 2:
2y=10-6x--->cross%282%29y%2Fcross%282%29=%2810-6x%29%2F2
y=10%2F2-%286%2F2%29x=5-3x
Let f%28x%29=0
y=5-3%280%29=highlight%285%29
Letf%28y%29=0
0=5-3x---->3x=5--->cross%283%29%2Ax%2Fcross%283%29=5%2F3
highlight%28x=5%2F3%29
Let's see the graph:
----->RED>>>> EQN1: GREEN>>>>EQN2
Thank you,
Jojo