SOLUTION: Suppose a family drives an average rate of 60mi/h on the way to visit relatives and then at an average rate of 40mi/h on the way back. The return trip takes 1h longer than the trip

Algebra ->  Coordinate Systems and Linear Equations  -> Lessons  -> Linear Equations Lesson -> SOLUTION: Suppose a family drives an average rate of 60mi/h on the way to visit relatives and then at an average rate of 40mi/h on the way back. The return trip takes 1h longer than the trip      Log On


   

Question 1191968: Suppose a family drives an average rate of 60mi/h on the way to visit relatives and then at an average rate of 40mi/h on the way back. The return trip takes 1h longer than the trip there.
a. Let d be the distance in miles the family traveled to visit their relatives. How many hours did they take to drive there?
b. In terms of d, how many hours did it take to make the return trip?
c. Write and solve an equation to determine the distance the family traveled to see their relatives. What was the average rate for the entire trip?
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
             SPEED          TIME              DIST.

GOING          60           d/60                 d

RETURN         40           d/40                 d

DIFF.                         1

d%2F40-d%2F60=1
Simplify and solve for d.