SOLUTION: which of the following regions (I, II, III, or IV) formed by the intersection of two linear inequalities will represent the common solution area of the system of the following ineq

Algebra ->  Coordinate Systems and Linear Equations  -> Lessons  -> Linear Equations Lesson -> SOLUTION: which of the following regions (I, II, III, or IV) formed by the intersection of two linear inequalities will represent the common solution area of the system of the following ineq      Log On


   

Question 1190838: which of the following regions (I, II, III, or IV) formed by the intersection of two linear inequalities will represent the common solution area of the system of the following inequalities?
x + 3y > -4
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3x - 2y < 5
Found 2 solutions by MathLover1, greenestamps:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

x+%2B+3y+%3E+-4
3x+-+2y+%3C+5
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The solutions to a system of linear inequalities are located in the region where all the shaded regions of the inequalities overlap. What is the region of overlap called? Intersection!
The intersection of two linear inequalities will represent the common solution area.
In your case intersection point is in Q IV.

Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


The wording of the problem is extremely poor.

The points that satisfy the system of inequalities lie in PARTS of ALL FOUR quadrants.

No one quadrant "represents" the common solution area; likewise, no combination of more than one quadrant "represents" the common solution area.