SOLUTION: Find an equation of the line perpendicular to 6y=x+2 that passes through the point (3,1). Write the answer in slope-intercept form, y=mx+b, with all fractions written in lowest ter

Algebra ->  Coordinate Systems and Linear Equations  -> Lessons  -> Linear Equations Lesson -> SOLUTION: Find an equation of the line perpendicular to 6y=x+2 that passes through the point (3,1). Write the answer in slope-intercept form, y=mx+b, with all fractions written in lowest ter      Log On


   

Question 1169654: Find an equation of the line perpendicular to 6y=x+2 that passes through the point (3,1). Write the answer in slope-intercept form, y=mx+b, with all fractions written in lowest terms.
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

Find an equation of the line perpendicular to 6y=x%2B2 that passes through the point (3,1).
If two lines are perpendicular, the slopes are negative reciprocals.
so, find a slope of 6y=x%2B2
y=x%2F6%2B2%2F6

y=%281%2F6%29x%2B1%2F3=> slope m=1%2F6
-> negative reciprocal is -1%2Fm=-1%2F%281%2F6%29=-6
so, the slope of the perpendicular line is -6
then perpendicular line will be:
y=mx%2Bb........substitute slope =-6
y=-6x%2Bb.......use given point (3,1) to calculate b
1=-6%2A3%2Bb
1=-18%2Bb
b=1%2B18
b=19
and your equation is: y=-6x%2B19