Question 1134703: Solve the equations using elimination and substitution
（1）2x+3y=11
4x+y=12
（2）3x+2y=24
2x-3y=42 Found 2 solutions by Boreal, MathLover1:Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! First by substitution
y=-4x+12
substitute into the top to get 2x+3(-4x+12)=11
2x-12x+36=11
-10x=-25
x=2.5
substitute into second and y=2
check in top one and 2(2.5)+3(2) does =11
(2.5, 2)
Do by elimination
multiply top by -2
-4x-6y=-22
4x+y=12
-5y=-10
y=2
x=2.5
Do the second by elimination
Multiply the top by 3 and the bottom by 2, which will make 6y and -6y which cancel each other
9x+6y=72
4x-6y=84
13x=156
x=12
y=-6
(12, -6), and that checks
One can do substitution but more difficult here. x=(-2/3)y+8 or y=(-3/2)x+12 and put into the second equation.
You can put this solution on YOUR website!
（1）
.....eq.1 ......eq.2
------------------------
start with
......eq.2...solve for .......eq.2a...substitute in eq.1 to eliminate variable
.....eq.1
...solve for
go back to eq.2a, substitute for
solution is intersection point (,)=(,)
（2）
.......eq.1 .......eq.2
---------------------------
start with
.......eq.1 ..solve for ...........eq.1a
go to .......eq.2...substitute in from eq.1a to eliminate variable .........both sides multiply by
go back to eq.1a
...........eq.1a substitute for and solve for
