SOLUTION: 3x-2y-z=3 2x-y+z=4 x-2y+3z=3

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Question 1016604: 3x-2y-z=3
2x-y+z=4
x-2y+3z=3

Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!


If we add the first equation to the second, 
the z's will cancel:





To make the z's cancel in the first
and third equations, we multiply the first 
equation through by 3:



Add the first equation to the third equation:



To make the x's cancel, divide the third
equation by -2



Add the third equation to the second equations:



Substitute 1 for y in the second equation



Multiply 3 by 1 in the second equation



Add 3 to both side of the second equation:



Divide the second equation through by 5



Substitute 1 for y and 2 for x in the first equation:



Multiply 9 by 2 and 6 by 1:



Combine 18-6 as 12 in the first eqauation



Subtract 12 from both sides of the first equation



Divide the first equation through by -3



Edwin