SOLUTION: The side of a square house is 24 feet long and the house is located on a lot which is 50 feet longer than it is wide. The perimeter of the lot is 20 feet more than five times the p

Algebra ->  Coordinate Systems and Linear Equations  -> Lessons  -> Linear Equations Lesson -> SOLUTION: The side of a square house is 24 feet long and the house is located on a lot which is 50 feet longer than it is wide. The perimeter of the lot is 20 feet more than five times the p      Log On


   

Question 1012924: The side of a square house is 24 feet long and the house is located on a lot which is 50 feet longer than it is wide. The perimeter of the lot is 20 feet more than five times the perimeter of the house. find the length of the lot.
Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
If the house is square and has a side of 24 feet, its perimeter must be 96 feet.
For the lot, we have perimeter
P = 2L + 2W = 5(96) + 20
and
L = 50 + W
Now substitute this into the first equation and get
2(50+W) + 2W = 5(96) + 20
100 + 2W + 2W = 480 + 20 = 500
Subtract 100 and get
4W = 400
W = 100 feet
L = 50+W = 150 feet