SOLUTION: Find value of 'a' when y=(4a-6)x and y= 1/5x

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Question 1006759: Find value of 'a' when y=(4a-6)x and y= 1/5x
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find a; given;y=(4a-6)x and y=1/5x
y=4ax-6x
1/5x=4ax-6x
(5x)(1/5x)=(5x)(4ax)-(5x)(6x)
1=20ax^2-30x^2
30x^2+1=20ax^2-30x^2+30x^2
30x^2+1=20ax^2
(30x^2+1)/(20x^2)=(20ax^2)/(20x^2)
(30x^2+1)/(20x^2)=a