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This Lesson (Using system of two equations to solve the problem for the day of April, 1) was created by by ikleyn(52921)
  About ikleyn: Using system of two equations to solve the problem for the day of April, 1Problem 1You burn approximately 230 calories less per hour if you ride your bike versus go on a run.Lien went on a 2-hour run plus burned an additional 150 calories in his warm up and cool down. Theo went on a 4-Hour bike ride. Lien and Theo burned the same amount of calories on their workouts. Approximately how many calories do you burn in an hour for each type of exercise? Solution
Let B is the number of calories you (actually, "average person") burn per hour riding bike (Bike; B stands for Bike), and
let R is the number of calories you (actually, "average person") burn per hour running (Running; R stands for Running).
Then the condition gives you these two equations
R - B = 230, (1) ("You burn approximately 230 calories less per hour if you ride your bike versus go on a run. ")
2R + 150 = 4B (2) ("Lien and Theo burned the same amount of calories on their workouts.")
Thus the major part of the solution is just done: the Math model is established.
The rest is just arithmetic and techniques.
For me, this problem is good for the day of April, 1, when somebody wants to make other people smile or to be surprised. When I saw this problem for the first time, my first reaction after reading the condition was "it is absurd !". But later, carefully thinking about it, I suddenly found the problem's hidden meaning, and was really happy . . . Therefore, I think it is a good idea to present this unexpected and amazing problem in the lesson under this title ! ----------------------- April, 1 is an International Fools' dayFor further info see this Wikipedia article
https://en.wikipedia.org/wiki/April_Fools%27_Day
My other lessons in this site on solving systems of two linear equations in two unknowns (Algebra-I curriculum) are - Solution of the linear system of two equations in two unknowns by the Substitution method - Solution of the linear system of two equations in two unknowns by the Elimination method - Solution of the linear system of two equations in two unknowns using determinant - Geometric interpretation of the linear system of two equations in two unknowns - Useful tricks when solving systems of 2 equations in 2 unknowns by the Substitution method - Solving word problems using linear systems of two equations in two unknowns - Word problems that lead to a simple system of two equations in two unknowns - Oranges and grapefruits - Using systems of equations to solve problems on tickets - Three methods for solving standard (typical) problems on tickets - Using systems of equations to solve problems on shares - Using systems of equations to solve problems on investment - Two mechanics work on a car - The Robinson family and the Sanders family each used their sprinklers last summer - Roses and vilolets - Counting calories and grams of fat in combined food - A theater group made appearances in two cities - Exchange problems solved using systems of linear equations - Typical word problems on systems of 2 equations in 2 unknowns - HOW TO algebraize and solve these problems on 2 equations in 2 unknowns - One unusual problem to solve using system of two equations - Non-standard problem with a tricky setup - Sometimes one equation is enough to find two unknowns in a unique way - Solving mentally word problems on two equations in two unknowns - Solving systems of non-linear equations by reducing to linear ones - Solving word problems for 3 unknowns by reducing to equations in 2 unknowns - System of equations helps to solve a problem for the Thanksgiving day - OVERVIEW of lessons on solving systems of two linear equations in two unknowns Use this file/link ALGEBRA-I - YOUR ONLINE TEXTBOOK to navigate over all topics and lessons of the online textbook ALGEBRA-I. This lesson has been accessed 2364 times. |
