SOLUTION: im sorry i have one more question: did i get this right? the problem was:-1.5x+0.3y=-7.2, 3x-0.6y=14.4 once more i had addition/elimination method. heres what i got, 0=-43.2 or

Algebra ->  Coordinate Systems and Linear Equations  -> Lessons -> SOLUTION: im sorry i have one more question: did i get this right? the problem was:-1.5x+0.3y=-7.2, 3x-0.6y=14.4 once more i had addition/elimination method. heres what i got, 0=-43.2 or       Log On


   



Question 999101: im sorry i have one more question:
did i get this right? the problem was:-1.5x+0.3y=-7.2, 3x-0.6y=14.4
once more i had addition/elimination method. heres what i got, 0=-43.2 or
no solution

Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
i didn't get that.

your equations are:

-1.5x + .3y = -7.2
3x - .6y = 14.4

multiply both sides of the first equation by 2 and leave the second equation as is to get:

-3x + .6y = -14.4
3x - .6y = 14.4

add the equations together to get:

0x + 0y = 0 which becomes 0 = 0

since you get 0 = 0, there are infinitely many solutions and the graphs of the lines are identical.

in standard form of a linear equation, if the equations are multiples of each other, then they are identical to each other.

these equations are multiples of each other as you will see in a moment.

the two equations are:

-1.5x + .3y = -7.2
3x - .6y = 14.4

multiply both sides of the first equation by -1 and leave the second equation as is and you get:

1.5x - .3y = 7.2
3x - .6y = 14.4

3 is twice 1.5
.6 is twice .3
14.4 is twice 7.2

the equations are multiplies of each other in standard form, therefore identical.

every point on the line of the first equation will also be on the line of the second equation.

when graphed, both equations look like the same line.