SOLUTION: a number plus two third of itself plus one half of itself plus one seventh of itself equal 97. find the no.

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Question 99701: a number plus two third of itself plus one half of itself plus one seventh of itself equal 97. find the no.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
a number plus two third of itself
12%2F3x = 5%2F3x
:
plus one half of itself
+ 1%2F2x
:
plus one seventh of itself
+ 1%2F7x
:
equal 97.
5%2F3x + 1%2F2x + 1%2F7x = 97
:
find the no.
:
A multiple of all 3 denominators is 42:
42*5%2F3x + 42*1%2F2x + 42*1%2F7x = 42(97)
:
CAncel out the denominators:
14(5x) + 21x + 6x = 4074
:
70x + 21x + 6x = 4074
:
97x = 4074
:
x = 4074/97
:
x = 42
:
:
Check solution in original equation:
5%2F3*42 + 1%2F2*42 + 1%2F7*42 = 97
70 + 21 + 6 = 97
:
Pretty simple, right?