SOLUTION: Hello! I need help solving this: What is the vertex, axis of symmetry an x-intercepts of f(x)=(x-7)^2+8 ? Please explain each step thank you.

Algebra ->  Coordinate Systems and Linear Equations  -> Lessons -> SOLUTION: Hello! I need help solving this: What is the vertex, axis of symmetry an x-intercepts of f(x)=(x-7)^2+8 ? Please explain each step thank you.      Log On


   

Question 976857: Hello!
I need help solving this:
What is the vertex, axis of symmetry an x-intercepts of f(x)=(x-7)^2+8 ?
Please explain each step thank you.
Answer by FrankM(1040) About Me  (Show Source):
You can put this solution on YOUR website!
y=%28x-7%29%5E2%2B8

I prefer the equation for vertex form as follows:

y-k=a%28x-h%29%5E2

where (h,k) is the vertex.

y-8=%28x-7%29%5E2

The vertex is (7,8)

The axis of symmetry is the line x=7 as it's a vertical line running through the vertex.

X intercepts are when Y=0, but with the vertex above the X axis, and the parabola opening up, there is no X intercept.
.