SOLUTION: 40/x+y + 2/x-y =5,25/x+y - 3/x-y=1,where x+y is not equal to 0 and x-y is not equal to 0

Algebra ->  Coordinate Systems and Linear Equations  -> Lessons -> SOLUTION: 40/x+y + 2/x-y =5,25/x+y - 3/x-y=1,where x+y is not equal to 0 and x-y is not equal to 0      Log On


   

Question 970028: 40/x+y + 2/x-y =5,25/x+y - 3/x-y=1,where x+y is not equal to 0 and x-y is not equal to 0
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Use a substitution,
A=1%2F%28x%2By%29
B=1%2F%28x-y%29
So then,
1.40A%2B2B=5
2.25A-3B=1
Multiply eq. 1 by 3 and eq. 2 by 2 and add them,
120A%2B6B%2B50A-6B=15%2B2
170A=17
A=1%2F10
So then,
40%2F10%2B2B=5
4%2B2B=5
2B=1
B=1%2F2
Substituting back,
1%2F%28x%2By%29=1%2F10
3.x%2By=10
.
.
1%2F%28x-y%29=1%2F2
4.x-y=2
Add eq. 3 to eq. 4,
x%2By%2Bx-y=10%2B2
2x=12
x=6
Then,
6%2By=10
y=4