Question 96367: how do i find sloope of an equation that looks like this
X-2/3y=1/4
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2X-5Y=0 Found 2 solutions by elima, checkley71:Answer by elima(1433) (Show Source):
You can put this solution on YOUR website! You need to put them in slope intercept form;
y=mx+b, where m = slope;
X-2/3y=1/4
subtract x from both sides:
-y=-x+
multiply the reciprocal of to both sides;
y=-x+
y=X-
slope =
2X-5Y=0
-5y=-2x+0
y=x
slope =
You can put this solution on YOUR website! Y=mX+b IS THE LINE EQUATION WHERE m=SLOPE. NOW PUT YOUR EQUATION IN THIS FORM:
X-2/3Y=1/4
-2/3Y=-X+1/4
Y=-X/(-2/3)+(1/4)/(-2/3) TO DIVIDE BY A FRACTION IN THE DENOMINATOR INVERT THE FRACTION IN THE DENOMINATOR & MULTIPLY BY THE NUMERATOR THUS:
Y=-X(-3/2)+(1/4)(-3/2)
Y=3X/2-3/8 THIS LINE HAS A SLOPE(m)=3/2
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2X-5Y=0
-5Y=-2X
Y=-2X/-5
Y=2X/5 THIS LINE HAS A SLOPE(m)=2/5
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