SOLUTION: I need to solve this system of linear equations using any method. I tried using the elimination method but i got stuck.
8x-6y=12
12x-9y=18 I started off by adding the 8x and 12
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-> SOLUTION: I need to solve this system of linear equations using any method. I tried using the elimination method but i got stuck.
8x-6y=12
12x-9y=18 I started off by adding the 8x and 12
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Question 951633: I need to solve this system of linear equations using any method. I tried using the elimination method but i got stuck.
8x-6y=12
12x-9y=18 I started off by adding the 8x and 12x and got 10x. then i added -6 and -9 and got -15. 12+18 and got 30. from there i was starting to feel iffy about the rest. if all this is right how do i go about finishing the problem off? Found 2 solutions by Alan3354, MathLover1:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! 8x-6y=12 divide by 2 ---> 4x - 3y = 4
12x-9y=18 divide by 3 --> 4x - 3y = 6
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Subtract
0 = -2
Inconsistent, no solution.
If you graph the 2 eqns, you get parallel lines.
No intersection, no solution.
You can put this solution on YOUR website! ....eq.1....simplify first, both sides divide by ....eq.2...both sides divide by....eq.1 ....eq.2
----------------------------now you got same coefficients for and variable which means the two lines are identical, so if you subtract eq.2 from eq.1 you will get
the two lines are identical if one lies perfectly on top of the other, and intersect at all points of both lines
