SOLUTION: It took Henri 50 h of cycling to finish his bike tour. On the return trip over the same route, he increased his cycling rate by 1 mi/h and took 45 h. What was his rate on the retur

Algebra ->  Coordinate Systems and Linear Equations  -> Lessons -> SOLUTION: It took Henri 50 h of cycling to finish his bike tour. On the return trip over the same route, he increased his cycling rate by 1 mi/h and took 45 h. What was his rate on the retur      Log On


   

Question 944910: It took Henri 50 h of cycling to finish his bike tour. On the return trip over the same route, he increased his cycling rate by 1 mi/h and took 45 h. What was his rate on the return trip.
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +r+ = his rate on the cycling tour
Let +d+ = distance of the cycling tour in miles
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Equation for the tour:
+d+=+r%2A50+
Equation for return trip:
+d+=+%28+r+%2B+1+%29%2A45+
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By substitution:
+50r+=+45r+%2B+45+
+5r+=+45+
+r+=+9+
+r+%2B+1+=+10+
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His rate on the return trip was 10 mi/hr
check:
+d+=+r%2A50+
+d+=+9%2A50+
+d+=+450+
and
+d+=+%28+r+%2B+1+%29%2A45+
+d+=+10%2A45+
+d+=+450+
OK