Question 944909: Leila left home at noon, traveling at 24 mi/h. An hour later her brother Josh, driving 36 mi/h, set out to over take her. How long did it take him? (Hint: let l = time leila's time in h, let j = josh's time in h.)
Found 2 solutions by Alan3354, josgarithmetic:
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! Leila left home at noon, traveling at 24 mi/h. An hour later her brother Josh, driving 36 mi/h, set out to over take her. How long did it take him?
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She's 24 miles ahead.
His speed relative to her is 12 mi/hr
24/12 = 2 hours
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Answer by josgarithmetic(39617)  (Show Source):
You can put this solution on YOUR website! The variable assignments here WILL be j for Josh's time, and therefore j+1 for Leila's time. At their individual rates and travel times, they reach the same distance, d.
____________________rate___________time______________distance
Leila_______________24_____________j+1________________d
Josh________________36______________j_________________d
d is the same value for both of them.
Solve for j.
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