SOLUTION: Solve each system by substitution. x = -1/4y + 5 3x + 2y = 0

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Question 938968: Solve each system by substitution.
x = -1/4y + 5
3x + 2y = 0
Answer by srinivas.g(540) About Me  (Show Source):
You can put this solution on YOUR website!
substitute x+=+%28-1%2F4%29y+%2B+5 in 3x + 2y = 0
++3%28%28-1%2F4%29y+%2B+5%29+%2B2y++=0
+%28-3%2F4%29y+%2B15+%2B2y=+0
++y%28%28-3%2F4%29+%2B2%29+%2B15+=+0
+y+%282-3%2F4%29+=-15
++y+%28+2%2A%284%2F4%29+-3%2F4%29=+-15
y%288%2F4+-3%2F4%29=+-15
+y%28%288-3%29%2F4%29+=+-15
+y%285%2F4%29++=+-15
+y++=+-15%2A%284%2F5%29
y= -12