SOLUTION: Please I would appreciate anyone's help. I am stuck on this problem. Solve by elimination or substitution. For all three variables a, b and c. Use all three equations. 5a-5b+5

Algebra ->  Coordinate Systems and Linear Equations  -> Lessons -> SOLUTION: Please I would appreciate anyone's help. I am stuck on this problem. Solve by elimination or substitution. For all three variables a, b and c. Use all three equations. 5a-5b+5      Log On


   

Question 928768: Please I would appreciate anyone's help. I am stuck on this problem.
Solve by elimination or substitution. For all three variables a, b and c. Use all three equations.
5a-5b+5c=25
-4a+4b-2c=-12
-a+ b-5c=-21
Answer by TimothyLamb(4379) About Me  (Show Source):
You can put this solution on YOUR website!
5a-5b+5c=25
-4a+4b-2c=-12
-a+ b-5c=-21
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put the system of linear equations into standard form
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substitute:
x for a
y for b
z for c
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5x-5y+5z=25
-4x+4y-2z=-12
-x+ y-5z=-21
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answer:
This linear system is singular. It has no solution
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