SOLUTION: the width of a rectangular lot is 75% of its length. if the perimeter is 700 meter, then what are the length and width?

Algebra ->  Coordinate Systems and Linear Equations  -> Lessons -> SOLUTION: the width of a rectangular lot is 75% of its length. if the perimeter is 700 meter, then what are the length and width?      Log On


   



Question 927120: the width of a rectangular lot is 75% of its length. if the perimeter is 700 meter, then what are the length and width?
Answer by EMStelley(208) About Me  (Show Source):
You can put this solution on YOUR website!
Let's start by naming a variable. We will name length l. Then "the width of a rectangular lot is 75% of its length" is telling us that the width w is equal to 0.75l. So our length and width can be represented as l and 0.75l. Now, remembering that perimeter is 2l+2w (the sum of all of the sides), we can rewrite this as 2l+2(0.75l). In the problem they told us that the perimeter is 700 meters, so we have:
700=2l%2B2%280.75l%29
700=2l%2B1.5l
700=3.5l
200=l
So the length of the rectangular lot is 200 meters. Now to find the width, we use the fact that the width is 0.75l, so 0.75(200) is 150. So the length is 200 meters and the width is 150 meters.