SOLUTION: The sum of the digits of a three digit number is 13. When 11 is subtracted from the sum of the hundreds digit and tens digit, the answer is equal to the units digit. Additionally,

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Question 902070: The sum of the digits of a three digit number is 13. When 11 is subtracted from the sum of the hundreds digit and tens digit, the answer is equal to the units digit. Additionally, when the digits are reversed, the new value is 495 less than the original number.
Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
h = hundreds digit
t = tens digit
u = ones or units digit
100h+10t+u = the number
100u+10t+h = the number reversed

The sum of the digits of a three digit number is 13. 
h + t + u = 13

When 11 is subtracted from the sum of the hundreds digit and tens digit, the answer is equal to the units digit. 
 (h+t) - 11 = u
 h + t - 11 = u
  h + t - u = 11

Additionally, when the digits are reversed, the new value is 495 less than the original number.
    100u+10t+h = (100h+10t+u) - 495
100u + 10t + h = 100h + 10t + u - 495
     99u - 99h = -495                 <-- divide thru by 99 
         u - h = -5                   <-- get in h,t,u order 
        -h + u = -5                   

system%28h+%2B+t+%2B+u+=+13%2C+h+%2B+t+-+u+=+11%2C-h+%2B+u+=+-5%29

Can you solve that system?  If not post again asking how.

The number is 661 

Edwin