SOLUTION: solve following system by elimination:(addition) 4x-y=3 2x+3y=19 I got 4x -y =3 -4x -6y=-38 I know the 4x and -4x gets canceled, so do i get -7y=-34 and then y=-27 an

Algebra ->  Coordinate Systems and Linear Equations  -> Lessons -> SOLUTION: solve following system by elimination:(addition) 4x-y=3 2x+3y=19 I got 4x -y =3 -4x -6y=-38 I know the 4x and -4x gets canceled, so do i get -7y=-34 and then y=-27 an      Log On


   

Question 899030: solve following system by elimination:(addition)
4x-y=3
2x+3y=19
I got 4x -y =3
-4x -6y=-38
I know the 4x and -4x gets canceled, so do i get -7y=-34 and then y=-27 and plug it like 4x-(-27)=3? Not sure if I am doing this right.
Thanks in advance
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
You're on the right track but made some mistakes.
4x-y=3
-4x-6y=-38
Now adding them,
4x-y-4x-6y=3-38
-7y=-35
y=%28-35%29%2F%28-7%29
y=5
Now plug in the value for y into either equation and solve for x.