SOLUTION: What value of y forms the solution of the system defined by y = 11x + 1 and 11x + 12y = 12?

y = 11x + 1 
11x + 12y = 12

Take the right side of the first equation, which is 11x + 1,
since y equals it, put it in parentheses like this (11x + 1)
and put it in place of y in the second equation.

The second equation is

11x + 12y = 12

Take out the y and put in (11x + 1) in place of the y:

11x + 12(11x + 1) = 12

Remove the parentheses by using the distributive principle:

11x + 132x + 12 = 12

Combine like terms on the left

143x + 12 = 12

Subtract 12 from both sides

143x = 0

Divide both sides by 143

x = 0

Now go back and get the very first equation:

y = 11x + 1

And substitute (0) for x:

y = 11(0) + 1

y = 0 + 1

y = 1

That's the answer because the question asked for y.

Edwin

y = 11x + 1

11x   - y = -  1 ----- eq (i)

11x + 12y =   12 ----- eq (ii)

    - 13y = - 13 ----- Subtracting eq (ii) from eq (i)

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