Question 893074: A Carpenter and a helper can do a certain job in 15 days. If the Carpenter works 1.5 times as fast as the helper, how long would it take each to do the job, working alone?
Found 3 solutions by josgarithmetic, MathTherapy, richwmiller:
Answer by josgarithmetic(39617)   (Show Source):
You can put this solution on YOUR website! More than one way to do this.
RATES:
Carpenter, (3/2)r
Helper, r
Carpenter&Helper, 1/15
Unit is jobs per day.
Combined rate is their sum.
Solve for r and find its reciprocal; and this is how many days the helper needs to do 1 job.
Answer by MathTherapy(10552)  (Show Source):
You can put this solution on YOUR website!
A Carpenter and a helper can do a certain job in 15 days. If the Carpenter works 1.5 times as fast as the helper, how long would it take each to do the job, working alone?
Carpenter:  days
Helper:  days
You can do the check!!
If you need a complete and detailed solution, let me know!!
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Answer by richwmiller(17219)  (Show Source):
You can put this solution on YOUR website! h=1.5c
1/c+1/1.5c=1/15
multiply by 15c
15+15/1.5=c
15+10=c
c=25
h=37.5
check
1/25+1/37.5=1/15
2/50+2/75=2/30
6/150+4/150=10/150
ok
but
(3/2)r+r=1/15
45/2r+15r=1
3r+2r=2/15
45r+30r=2
75r=2
r=2/75
r=1/37.5
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