SOLUTION: Solve the system(Addition method recommended) 2x^2-4y^2=-14 2x^2+3y^2=98

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Question 866828: Solve the system(Addition method recommended)
2x^2-4y^2=-14
2x^2+3y^2=98
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

2x^2-4y^2=-14    |multiplying thru by -1 to  eliminate the x variable by adding the Eqs

2x^2+3y^2=98

      7y^2 = 112

        y^2 = 16

        y = ±4  and x = ±5  2x%5E2+=+-14+%2B+4%2A16 2x^2 = 50, x^2 = 25

(-5,-4), (-5,4), (5,-4), (5,4)  are the solutions for this system