SOLUTION: Can someone tell me where I am going wrong with trying to solve by elimination? 8x-3y=-6 5x+6y=75 5(8x-3y=-6) 40x-15y=-30 5x+6y=75 --

Algebra ->  Coordinate Systems and Linear Equations  -> Lessons -> SOLUTION: Can someone tell me where I am going wrong with trying to solve by elimination? 8x-3y=-6 5x+6y=75 5(8x-3y=-6) 40x-15y=-30 5x+6y=75 --      Log On


   

Question 862063: Can someone tell me where I am going wrong with trying to solve by elimination?
8x-3y=-6
5x+6y=75
5(8x-3y=-6) 40x-15y=-30
5x+6y=75
------------
35x-9y =45
Then I am stuck! Do I divide by 35x by 35 and 45 by 35? I am so confused at the moment.

Found 2 solutions by solver91311, richwmiller:
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Your first step was correct, namely multiplying the first equation by 5, but then you need to multiply the second equation by -8. Only then can you add the two equations and eliminate the variable.

John

My calculator said it, I believe it, that settles it
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Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
It would be easier to multiply the first 8x-3y=-6 by 2 and then add the new equation to the second equation 5x+6y=75 so that you eliminate y
since -6y+6y=0