SOLUTION: How Do I graph this Linear Equation, and find it's slope? The x + y part instead of the basic mx+b confuses me 12x+4y=8 Thanks.

Algebra ->  Coordinate Systems and Linear Equations  -> Lessons -> SOLUTION: How Do I graph this Linear Equation, and find it's slope? The x + y part instead of the basic mx+b confuses me 12x+4y=8 Thanks.      Log On


   



Question 8570: How Do I graph this Linear Equation, and find it's slope? The x + y part instead of the basic mx+b confuses me
12x+4y=8
Thanks.

Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
First convert from standard form Ax+By=C into slope intercept form by solving for y.

12x + 4y = 8 Subtract 12x from each side of the equation.
4y = -12x + 8

Next, divide both sides by 4:
+%284y%29%2F4+=+%28-12x%29%2F4+%2B+8%2F4
y+=+-3x+%2B+2

When the equation is in slope-intercept form, the slope is the coefficient of x, which is this case is -3.

R^2 from SCC after three weeks away!!