Question 847396: how to solve this
substitution method
5x-3y+3=0
6x-5y-2=0
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! solve this
substitution method
5x-3y+3=0
6x-5y-2=0
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Solve for "x" in the top equation::
x = (3/5)(y+1)
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Substitute for "x" and solve for "y":
6x - 5y - 2 = 0
(18/5)(y+1)-5y-2 = 0
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Multiply thru by 5 to get:
18y+18 - 25y - 10 = 0
-7y = -8
y = 8/7
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Solve for "x":
x = (3/5)(y+1)
x = (3/5)(15/7)
x = 45/35
x = 9/7
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Cheers,
Stan H.
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