SOLUTION: hello, We have a story problem, and have to solve it with a linear equation, either substitution, elimination, tables, y1-y2, or graphs. We have tried the substitution method on th

Algebra ->  Coordinate Systems and Linear Equations  -> Lessons -> SOLUTION: hello, We have a story problem, and have to solve it with a linear equation, either substitution, elimination, tables, y1-y2, or graphs. We have tried the substitution method on th      Log On


   

Question 835695: hello, We have a story problem, and have to solve it with a linear equation, either substitution, elimination, tables, y1-y2, or graphs. We have tried the substitution method on this problem, and can't seem to figure out what we are doing wrong. is there something different we need to be doing?
Antonio loves to go to the movies. he goes both at night and during the day. The cost of a matinee is $6.00. The cost of an evening show is $8.00. If antonio went to see a total of 12 movies and spent $86, how many night movies did he attend?
Thank you
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
A more complete question is, how many night movies and how many matinee or day movies, did Antonio attend?

ASSIGN VARIABLES.
x = count of daytime movies (matinees?)
y = count of night time movies

PRICES:
Matinees are 6 dollars/movie
Night movies are 8 dollars/movie

The total of 12 means that x%2By=12

The total spent $86 means that 6x%2B8y=86

THOSE are your two simultaneous equations for the system. Using either substitution or elimination should be a simple matter from here. Before either method, simplify the cost equation first. Use it as 3x%2B4y=43, after both sides divided by 2.


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If chose elimination, multiply the movie count equation by 3 on both sides...