SOLUTION: Please help me with this equation: y-22-3x. It says that we must find the x-intercept and the y-intercept. I got the y-intercept, I'm just confused on the x-intercept. Please help.

Algebra ->  Coordinate Systems and Linear Equations  -> Lessons -> SOLUTION: Please help me with this equation: y-22-3x. It says that we must find the x-intercept and the y-intercept. I got the y-intercept, I'm just confused on the x-intercept. Please help.      Log On


   



Question 835197: Please help me with this equation: y-22-3x. It says that we must find the x-intercept and the y-intercept. I got the y-intercept, I'm just confused on the x-intercept. Please help. Thank you for your time.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
If the equation is y+=+-22-3x, then you plug in y = 0 and solve for x

y+=+-22-3x

0+=+-22-3x

22+=+-3x

22%2F%28-3%29+=+x

x+=+-22%2F3

So the x-intercept is x+=+-22%2F3

Note: -22%2F3+=+-7.33333 (approximately)

-------------------------------------------------------

If the equation is y+=+22-3x, then you plug in y = 0 and solve for x

y+=+22-3x

0+=+22-3x

-22+=+-3x

-22%2F%28-3%29+=+x

x+=+22%2F3

So the x-intercept is x+=+22%2F3

Note: 22%2F3+=+7.33333 (approximately)