SOLUTION: How do you solve by graphing y<2x+4. and. -3x-2y>=6

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Question 829792: How do you solve by graphing y<2x+4. and. -3x-2y>=6
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
Put each inequality into slope-intercept form. Graph the line of each, but because both statements are INEQUALITIES, the strict inequality needs a dotted line, and the inclusive inequality needs a solid line.

Shade each half-plane for the two inequalities; the intersection of these shadings will be the solutions for the system of inequalities.

This statement already is set for graphing: y%3C2x%2B4

The other statement is worth transforming: -3x-2y%3E=6
-2y%3E=3x%2B6
y%3C=-%283%2F2%29x-3----- Easier to graph it this way.

Shade the region below the line of y%3C2x%2B4 using strokes in one direction.
Shade the region below the line of y%3C=-%283%2F2%29x-3 using strokes in a different direction than for the other line. This will make the intersection of shadings very easy to see.