Question 828828: solve for x,y, and z in the system of equations below. Explain your steps!!!???
x+7y+3z=29
3z+x-2y=-7
5y=10-2x
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! ---
x+7y+3z=29
3z+x-2y=-7
5y=10-2x
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put the system of linear equations into standard form:
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x+7y+3z=29
x-2y+3z=-7
2x+5y=10
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solution by matrix method:
x = -5
y = 4
z = 2
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now elimination method:
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x+7y+3z=29
(x-2y+3z=-7)*-1
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x+7y+3z=29
-x+2y-3z=7
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add subsystem:
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9y=36
y = 4
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(x+7y+3z=29)*-2
2x+5y=10
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-2x-14(4)-6z=-58
2x+5(4)=10
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add subsystem:
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-36 - 6z =-48
-6z =-12
z = 2
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x+7y+3z=29
x=29-7y-3z
x=29-7(4)-3(2)
x = -5
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solution by elimination method:
x = -5
y = 4
z = 2
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both methods agree !
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