SOLUTION: A snack food is made by mixing 6 lb of popcorn that costs $.80 per pound with caramel that costs $2.30 per pound. How much caramel is needed to make a mixture that costs $1.40 per

Algebra ->  Coordinate Systems and Linear Equations  -> Lessons -> SOLUTION: A snack food is made by mixing 6 lb of popcorn that costs $.80 per pound with caramel that costs $2.30 per pound. How much caramel is needed to make a mixture that costs $1.40 per       Log On


   



Question 802588: A snack food is made by mixing 6 lb of popcorn that costs $.80 per pound with caramel that costs $2.30 per pound. How much caramel is needed to make a mixture that costs $1.40 per pound?

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +c+ = pounds of caramel needed
+2.3c+ = cost of the caramel used
+.8%2A6+=+4.8+ = cost of the popcorn used
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+%28+4.8+%2B+2.3c+%29+%2F+%28+6+%2B+c+%29+=+1.4+
+4.8+%2B+2.3c+=+1.4%2A%28+6+%2B+c+%29+
+4.8+%2B+2.3c+=+8.4+%2B+1.4c+
+.9c+=+3.6+
+c+=+4+
4 pounds of caramel is needed
check:
+%28+4.8+%2B+2.3c+%29+%2F+%28+6+%2B+c+%29+=+1.4+
+%28+4.8+%2B+2.3%2A4+%29+%2F+%28+6+%2B+4+%29+=+1.4+
+%28+4.8+%2B+9.2+%29+%2F+10+=+1.4+
+14+=+1.4%2A10+
+14+=+14+
OK